1.
[tex]a) \ \sqrt{64}+\sqrt{144}+\sqrt{196} = \sqrt{8^{2}}+\sqrt{12^{2}}+\sqrt{14^{2}} =8+12+14=34\\\\b) \ \sqrt{625}-\sqrt{225} = \sqrt{25^{2}}-\sqrt{15^{2}} = 25-15 = 10[/tex]
2.
[tex]\sqrt{(\frac{1}{3})^{2}}=\frac{1}{3}\approx0,33\\\\(\sqrt{0,5^{2}})^{2} = 0,5^{2} = 0,25\\\\(\sqrt{0,36})^{2}} = 0,36\\\\0,25 < 0,33 < 0,36\\\\\underline{(\sqrt{0,5^{2}})^{2} < \sqrt{(\frac{1}{3})^{2}}<(\sqrt{0,36})^{2}}[/tex]
3.
[tex]\sqrt{\frac{121}{25}} = \frac{\sqrt{121}}{\sqrt{25}} = \frac{11}{5} \ \ \in Q\\\\\sqrt{0,04} = 0,2 = \frac{2}{10} = \frac{1}{5} \ \ \in Q\\\\\sqrt{676} = 26=\frac{26}{1} \ \ \in Q\\\\\sqrt{\frac{1}{6}} \ \ \notin Q\\\\\boxed{Odp. \ A}[/tex]
(Q - zbiór liczb wymiernych, czyli takich liczb, które można zapisać w postaci ułamka p/q dla q ≠0)
