Odpowiedź:
[tex]a)\ \ \sqrt{3}\cdot\sqrt{5}\cdot\sqrt{15}=\sqrt{15}\cdot\sqrt{15}=\sqrt{15\cdot15}=\sqrt{15^2}=15\\\\\\b)\ \ \sqrt{\frac{4}{5}}\cdot\sqrt{0,6}\cdot\sqrt{12}=\sqrt{\frac{4}{5}\cdot0,6\cdot12}=\sqrt{\frac{4}{5}\cdot\frac{3}{5}\cdot12}=\sqrt{\frac{12}{25}\cdot12}=\sqrt{\frac{144}{25}}=\frac{12}{5}=2\frac{2}{5}[/tex]
[tex]c)\ \ \sqrt[3]{1\frac{1}{5}}\cdot\sqrt[3]{2,5}\cdot\sqrt[3]{1\frac{1}{8}}=\sqrt[3]{1\frac{1}{5}\cdot2,5\cdot1\frac{1}{8}}=\sqrt[3]{\frac{6}{5}\cdot\frac{25}{10}\cdot\frac{9}{8}}=\sqrt[3]{\frac{\not6^3}{\not5_{1}}\cdot\frac{\not5^1}{\not2_{1}}\cdot\frac{9}{8}}=\sqrt[3]{3\cdot\frac{9}{8}}=\\\\=\sqrt[3]{\frac{27}{8}}=\frac{3}{2}=1\frac{1}{2}[/tex]
