Odpowiedź :
[tex]x+\dfrac{1}{x}=8\\\left(x+\dfrac{1}{x}\right)^2=64\\x^2+2+\left(\dfrac{1}{x}\right)^2=64\\x^2+\left(\dfrac{1}{x}\right)^2=62[/tex]
[tex]x+\dfrac{1}{x}=8\\\left(x+\dfrac{1}{x}\right)^2=64\\x^2+2+\left(\dfrac{1}{x}\right)^2=64\\x^2+\left(\dfrac{1}{x}\right)^2=62[/tex]