Odpowiedź :
[tex]a)\\c-5m = k\\\\-5m = k-c \ \ /:(-5)\\\\m = \frac{c-k}{5}[/tex]
[tex]b)\\am+1 = t-am\\\\am+am = t-1\\\\2am = t-1 \ \ /:2a\\\\m = \frac{t-1}{2a}[/tex]
[tex]a)\\c-5m = k\\\\-5m = k-c \ \ /:(-5)\\\\m = \frac{c-k}{5}[/tex]
[tex]b)\\am+1 = t-am\\\\am+am = t-1\\\\2am = t-1 \ \ /:2a\\\\m = \frac{t-1}{2a}[/tex]