Odpowiedź:
(2x-4) (2x+4)=(3x-1) ^2-16
4x^2-16=9x^2-6x+1-16
4x^2=9x^2-6x+1
4x^2-9x^2+6x-1=0
-5x^2+6x-1=0
5x^2-6x+1=0
5x^2-x-5x+1=0
x(5x-1) -(5x-1)=0
(5x-1)(x-1)=0
5x-1=0
x-1=0
x=1/5
x=1
(2x - 4)(2x + 4) = 4x² - 2 * 2x * 1 - 16
4x² - 16 = 4x² - 4x + 1 - 16
4x² - 4x² = 1 - 16 + 16
4x = 1
x = 1/4
x = 0,25
