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OLABRYLA07OZRPH0ON
Rozwiązane

zapisz w postaci potegi liczby 10.
a) 1000¹¹
b) 100²⁰
c) 1000⁶⁰
d) (100⁷)⁶
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Odpowiedź :

cześć!

[tex] {1000}^{11} = {( {10}^{3}) }^{11} = {10}^{33} [/tex]

[tex] {100}^{20} = {( {10}^{2} )}^{20} = {10}^{40} [/tex]

[tex] {1000}^{60} = {( {10}^{3}) }^{60} = {10}^{180} [/tex]

[tex] {( {100}^{7}) }^{6} = {100}^{42} = {( {10}^{2}) }^{42} = {10}^{84} [/tex]

pozdrawiam!

PRZEMEKPIOTRON

a)

[tex] {1000}^{11} = { ({10}^{3}) }^{11} = {10}^{33} [/tex]

b)

[tex] {100}^{20} = { ({10}^{2} )}^{20} = {10}^{40} [/tex]

c)

[tex] {1000}^{60} = {( {10}^{3} )}^{60} = {10}^{180} [/tex]

d)

[tex] { ({100}^{7} )}^{6} = ({ ({ ({10}^{2}) }^{7} )}^{6}) = { ({10}^{14}) }^{6} = {10}^{84} [/tex]

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