Odpowiedź :
f(x)=(6-4m)x-18
A(6,-6)
[tex](6-4m)\cdot6-18=-6\\\\\(6-4m)\cdot6=-6+18\\\\(6-4m)\cdot6=12\ \ \ |:6\\\\6-4m=2\\\\-4m=2-6\\\\-4m=-4\ \ \ |:(-4)\\\\m=1[/tex]
f(x)=(6-4m)x-18
A(6,-6)
[tex](6-4m)\cdot6-18=-6\\\\\(6-4m)\cdot6=-6+18\\\\(6-4m)\cdot6=12\ \ \ |:6\\\\6-4m=2\\\\-4m=2-6\\\\-4m=-4\ \ \ |:(-4)\\\\m=1[/tex]