Odpowiedź:
[tex]\sqrt{\dfrac{4}{9}}*\sqrt{\dfrac{9}{16}}*\sqrt{\dfrac{16}{25}}=\dfrac{\not2^1}{\not3_{1} }*\dfrac{\not3^1}{\not4_{2}}*\dfrac{4}{5}=\dfrac{1}{\not2_{1}}*\dfrac{\not4^2}{5}=\dfrac{2}{5}[/tex]
