Rozwiązanie jest w załączniku.
sin120°=sin(90°+30°)=cos30°
cos120°=cos(90°+30°)=-sin30°
tg120°=tg(90°+30°)=-ctg30°
sin135°=sin(90°+45°)=cos45°
cos135°=cos(90°+45°)=-sin45°
tg135°=tg(90°+45°)=-ctg45°
sin150°=sin(90°+60°)=cos60°
cos150°=cos(90°+60°)=-sin60°
tg150°=tg(90°+60°)=-ctg60°
