Odpowiedź :
[tex](\sqrt6-\sqrt5)^x=\sqrt6+\sqrt5\\\\(\sqrt6-\sqrt5)^x=\dfrac{1}{\sqrt6-\sqrt5}\\\\\dfrac{1}{(\sqrt6-\sqrt5)^{-x}}=\dfrac{1}{\sqrt6-\sqrt5}\\\\-x=1\\x=-1[/tex]
[tex](\sqrt6-\sqrt5)^x=\sqrt6+\sqrt5\\\\(\sqrt6-\sqrt5)^x=\dfrac{1}{\sqrt6-\sqrt5}\\\\\dfrac{1}{(\sqrt6-\sqrt5)^{-x}}=\dfrac{1}{\sqrt6-\sqrt5}\\\\-x=1\\x=-1[/tex]