Odpowiedź:
[tex]Zad.10.\\a)(\frac{2}{10}) ^2=(\frac{1}{5} )^2=5^-^2\\b)(-\frac{1}{3})^3=-3^-^3\\ c)(-0,04)^6=(-\frac{4}{100} )^6=-4^-^6^0\\d)(\frac{1}{2^3} )=(\frac{1}{4})^3=4^-^3\\e)(\frac{1}{\sqrt[3]{27} } } )^2=(\frac{1}{3})^2=3^-^2\\ f)(\frac{-2}{\sqrt{16} })^3=(\frac{-2}{4})^3=(-\frac{1}{2})^3=-2^-^3\\ \\ Zad.11.\\ a) 4^-^2=(\frac{1}{4})^2=\frac{1}{16} \\ b) (-12)^-^3=(-\frac{1}{12})^3=-\frac{1}{1728}\\ c)(-\frac{3}{4})^-^1=-\frac{4}{3}= -1\frac{1}{3} \\[/tex]
[tex]d) (-1\frac{1}{3} )^-^2=(-\frac{4}{3})^-^2=(-\frac{3}{4} )^2=\frac{9}{16} \\e)(-0,3)^2=(-\frac{3}{10} )^-^2=(-\frac{10}{3} )^2=\frac{100}{9}=11\frac{1}{9} \\f)(\sqrt{3})^-^2=(\frac{1}{\sqrt{3} } ) ^2=\frac{1}{3}[/tex]
