Odpowiedź :
f(x) = 2(x-1)(ax+1) ; x ∈ R
a) a = 3
f(x) = 2(x-1)(3x+1)
x₀ = 1 V x₀ = -1/3
b)
-4 = 2(4-1)(4a+1)
-4 = 6(4a+1)
-4 = 24a + 6
-10 = 24a
a = -10/24
f(x) = 2(x-1)(ax+1) ; x ∈ R
a) a = 3
f(x) = 2(x-1)(3x+1)
x₀ = 1 V x₀ = -1/3
b)
-4 = 2(4-1)(4a+1)
-4 = 6(4a+1)
-4 = 24a + 6
-10 = 24a
a = -10/24