Odpowiedź :
Odpowiedź:
5/2x-2 - x+1/ 4x² -8x +4 < 2
5 / 2x - 2 - x + 1 < 8x² - 16x + 8
5 / 2x - 2 - x + 1 < 8(x² - 2x + 1)
5 < 8(x² - 2x + 1) * (2x - 2 - x + 1)
5 < 8(x² - 2x + 1) * (x - 1)
x² - 2x + 1 = 0 V x - 1 = 0
Δ = 0
[tex]x = \frac{-(-2)}{2* 1}[/tex]
x = 1 V x = 1
x ∈ (-∞, 5)