A ∪ B = (-∞; -[tex]\sqrt{2}[/tex])
A ∩ B = <-4;-2)
A \ B = (-∞;-4)
B \ A = <-2;-[tex]\sqrt{2}[/tex])
A ∪ B = (-π;∞)
A ∩ B = <[tex]-\frac{1}{2}[/tex];[tex]\frac{1}{2}[/tex]>
A \ B = ∅
B \ A = ([tex]\frac{1}{2}[/tex]; ∞)
A ∪ B = (-∞; ∞)
A ∩ B = {[tex]-\sqrt{3}[/tex]}
A \ B = (-∞; [tex]-\sqrt{3}[/tex])
B \ A = ([tex]-\sqrt{3}[/tex]; ∞)
