Odpowiedź:
a) = lim n³*( 4 - [tex]\frac{1}{n}[/tex] - [tex]\frac{2}{n^{2} }[/tex] + [tex]\frac{1}{n^3} )[/tex] = +∞
n⇒ ∞
b) = lim ( [tex]\frac{2}{3}[/tex] )^n - 4 = 0 - 4 = -4
n ⇒ ∞
c) = lim [tex]\frac{3 + \frac{1}{n} - \frac{1}{n^2} }{n - \frac{2}{n} + \frac{4}{n^2} }[/tex] = 0
n⇒∞
d) = lim [tex]\frac{\frac{4}{n } - n}{1 + \frac{2}{n} + \frac{1}{n^2} }[/tex] = -∞
e) = lim [tex]\sqrt{\frac{9 + \frac{1}{n} + \frac{4}{n^2} }{1 + \frac{1}{n} } }[/tex] = [tex]\sqrt{9}[/tex] = 3
Szczegółowe wyjaśnienie:
