[tex]Dane:\\m = 2 \ t = 2 \ 000 \ kg\\v = 72\frac{km}{h} = 72:3,6\frac{m}{s} = 20\frac{m}{s}\\r = 25 \ m\\Szukane:\\F_{d} = ?\\\\Rozwiazanie\\\\\underline{F_{d} = \frac{mv^{2}}{r}}\\\\F_{d} = \frac{2000 \ kg\cdot(20\frac{m}{s})^{2}}{25 \ m}=\frac{2000 \ kg\cdot400\frac{m^{2}}{s^{2}}}{25 \ m}\\\\\boxed{F_{d} = 32 \ 000 \ N = 32 \ kN}\\\\(1 \ kN = 1000 \ N)[/tex]
