Odpowiedź:
CH3CH2CH2COOH ⇒ CH3CH2CH2COO- + H+
[tex]\alpha = 0,002[/tex]
Cn= 0,01mol/dm3
[tex]\alpha = \frac{[H+]}{Co}[/tex]
[tex]0,02 = \frac{[H+]}{0,01mol/dm^{3}} /* 0,01mol/dm^{3} \\[/tex]
[tex]0,0002 = [H+][/tex]
pH = -log[H+]
pH = -log(0,0002) = 3,699
