Odpowiedź:
[tex] {2}^{8} \times {3}^{8} = (2 \times 3 {)}^{8} = {6}^{8} \\ ( \frac{1}{2} {)}^{7} \times ( \frac{5}{4} {)}^{7} = ( \frac{1}{2} \times \frac{5}{4} {)}^{7} = ( \frac{5}{8} {)}^{7} [/tex]
[tex] (\frac{1}{3} {)}^{9 } \div ( \frac{1}{2} {)}^{9} = ( \frac{1}{3} \div \frac{1}{2} {)}^{9} = ( \frac{1}{3} \times 2 {)}^{9} = ( \frac{2}{3} {)}^{9} [/tex]
[tex]( \frac{1}{6} {)}^{7} \div (\frac{1}{2} {)}^{7} = ( \frac{1}{6} \div \frac{1}{2} )^{7} = ( \frac{1}{6} \times 2 {)}^{7} = ( \frac{1}{3} {)}^{7} [/tex]
[tex](0.25 {)}^{4} \times (0.3 {)}^{4} = (0.25 \times 0.3 {)}^{4} = (0.075 {)}^{4} [/tex]
[tex](0.2 {)}^{7} \div (0.3 {)}^{7} = (0.2 \div 0.3 {)}^{7} = ( \frac{2}{10} \times \frac{10}{3} {)}^{7} = ( \frac{2}{3} {)}^{7} [/tex]
[tex](5x {)}^{2} = 25 {x}^{2} \\ (2 {a}^{2} {b}^{3} {)}^{2} = 4 {a}^{4} {b}^{6} \\ ( \frac{1}{2} x {y}^{2} {)}^{3} = \frac{1}{8} {x}^{3} {y}^{6} \\ ( \frac{1}{3} z {)}^{3} = \frac{1}{27} {z}^{3} [/tex]
