[tex]Dane:\\m = 800 \ kg\\F_{o} = 500 \ N\\F_{c} = 2 \ 500 \ N\\Szukane:\\F_{w} = ?\\a = ?[/tex]
[tex]Rozwiazanie[/tex]
[tex]F_{w} = F_{c}-F_{o} = 2500 \ N - 500 \ N = \boxed{2 \ 000 \ N = 2 \ kN}\\\\\\a = \frac{F_{w}}{m}\\\\a = \frac{2000 \ N}{800 \ kg} =\frac{2000 \ kg\cdot\frac{m}{s^{2}}}{800 \ kg}\\\\\boxed{a = 2,5\frac{m}{s^{2}}}[/tex]
Odp. Siła wypadkowa Fw = 2 000 N, przyspieszenie a = 2,5 m/s².
