Odpowiedź:
[tex]a)\ \ (2\sqrt{7})^2=2^2\cdot(\sqrt{7})^2=4\cdot7=28\\\\b)\ \ (\frac{3\sqrt{3}}{2})^2=\frac{3^2\cdot(\sqrt{3})^2}{2^2}=\frac{9\cdot3}{4}=\frac{27}{4}=6\frac{3}{4}\\\\c)\ \ 4\sqrt{5^2}=4\cdot5=20\\\\d)\ \ \frac{1}{3}\sqrt{6}\cdot3\sqrt{6}=\frac{1}{\not3_{1}}\cdot6\cdot\not3^1=6\\\\e)\ \ 7\sqrt[3]{5^3}=7\cdot5=35\\\\f)\ \ (2\sqrt[3]{3})^3=2^3\cdot(\sqrt[3]{3})^3=8\cdot3=24[/tex]
