[tex]h_1 = 4cm \\ \\ h_2 = 4cm \\ \\ h_3 = 2 \sqrt{2} cm[/tex]
[tex]d = a \sqrt{2} \\ d = 4 \sqrt{2} cm[/tex]
[tex](h_3 {)}^{2} + ({2 \sqrt{2} })^{2} = {4}^{2} \\ (h_3 {)}^{2} + 4 \times 2 = 16 \\ (h_3 {)}^{2} + 8 = 16 \\ (h_3 {)}^{2} = 8 \\ h_3 = \sqrt{8} = \sqrt{4 \times 2} = 2 \sqrt{2} cm[/tex]
