Odpowiedź:
AD=9
BC=5
DC = X
[tex] {x}^{2} = {6}^{2} + {2}^{2} \\ {x}^{2} = 36 + 4 \\ {x}^{2} = 40 \\ x = \sqrt{40} = 2 \sqrt{10} [/tex]
Obw =
[tex]9 + 5 + 2 \times 2\sqrt{10} = 14 + 4 \sqrt{10} [/tex]
