Odpowiedź:
3)
a)
A = ( - 2 , - 2 )
xa = - 2 , ya = - 2
Obliczamy promięń wodzacy punktu
r = √(xa² + ya²) = √[(- 2)² + (- 2)²] = √(4 + 4) = √(4 * 2) = 2√2
sinα = ya/r = - 2/2√2= - 1/√2 = - √2/2
cosα = xa/r = - 2/2√2 = - √2/2
tgα = ya/xa = - 2/(-2) = 2/2 = 1
ctgα = xa/ya = - 2/(- 2) = 2/2 = 1
b)
A = (- 4 , - 1 )
xa = - 4 , ya = - 1
r = √(xa² + ya²) = √[(- 4)² + (- 1)²] = √(16 + 1) = √17
sinα = ya/r = - 4/√17 = - 4√17/17
cosα = xa/r = - 1/√17 = - √17/17
tgα = ya/xa = - 1/(- 4) = 1/4
ctgα = xa/ya = - 4/(- 1) = 4
c)
A = (5 , 1 )
xa = 5 , ya = 1
r = √(xa² + ya²) = √(5² + 1²) = √(25 + 1) = √26
sinα = ya/r = 1/√26 = √26/26
cosα = xa/r = 5/√26 = 5√26/26
tgα = ya/xa = 1/5
ctgα =xa/ya = 5/1 = 5
