Odpowiedź:
[tex]a=4\ \ ,\ \ b=x-5\ \ ,\ \ c=36\\\\b^2=a\cdot c\\\\(x-5)^2=4\cdot36\\\\x^2-10x+25=144\\\\x^2-10x+25-144=0\\\\x^2-10x-119=0\\\\\Delta=b^2-4ac\\\\\Delta=(-10)^2-4\cdot1\cdot(-119)=100+476=576\\\\\sqrt{\Delta}=\sqrt{576}=24\\\\x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-24}{2\cdot1}=\frac{10-24}{2}=\frac{-14}{2}=-7\\\\x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+24}{2\cdot1}=\frac{10+24}{2}=\frac{34}{2}=17[/tex]
