Odpowiedź:
[tex](\frac{3}{2})^2\cdot(\frac{2}{3})^{-5}=(\frac{3}{2})^2\cdot(\frac{3}{2})^5=(\frac{3}{2})^{2+5}=(\frac{3}{2})^7=\frac{2187}{128}=17\frac{11}{128}[/tex]
[tex]( \frac{3}{2} {)}^{2} \times ( \frac{2}{3} {)}^{ - 5} = ( \frac{3}{2} {)}^{2} \times ( \frac{3}{2} {)}^{5} = ( \frac{3}{2} {)}^{7} = \frac{2187}{128} = 17 \frac{11}{128} [/tex]
