Odpowiedź :
[tex]pole = {a}^{2} \\ {a}^{2} = 48 \\ a = \sqrt{48} = \sqrt{16 \times 3} = 4 \sqrt{3} \\ d =a \sqrt{2} \\ d = 4 \sqrt{3} \times \sqrt{2} = 4 \sqrt{6} [/tex]
[tex]pole = {a}^{2} \\ {a}^{2} = 48 \\ a = \sqrt{48} = \sqrt{16 \times 3} = 4 \sqrt{3} \\ d =a \sqrt{2} \\ d = 4 \sqrt{3} \times \sqrt{2} = 4 \sqrt{6} [/tex]