Długość drugiej przyprostokątnej
[tex] {5}^{2} = {3}^{2} + {x}^{2} \\ 25 = 9 + {x}^{2} \\ {x}^{2} = 16 \\ x = \sqrt{16} \\ x = 4cm[/tex]
Pole podstawy
[tex] \frac{4 \times 3}{2} = \frac{12}{2} = 6 {cm}^{2} [/tex]
Objętość
[tex]6 \times 6 = \boxed{ 36 {cm}^{3} }[/tex]
P1
[tex]3 \times 6 = 18 {cm}^{2} [/tex]
P2
[tex]4 \times 6 = 24 {cm}^{2} [/tex]
P3
[tex]5 \times 6 = 30 {cm}^{2} [/tex]
Pole całkowite
[tex]18 + 24 + 30 + 2 \times 6 = 72 + 12 = \boxed{84 {cm}^{2}}[/tex]
