Odpowiedź:
Zadanie 4
[tex]b) \: 1 \frac{1}{4} \times 2 \frac{2}{3} = \frac{5}{4} \times \frac{8}{3} = \frac{10}{3} = 3 \frac{1}{3} [/tex]
[tex]c) \: 4\frac{5}{6} + 2 \frac{1}{4} = 4 \frac{10}{12} + 2 \frac{3}{12} = 6 \frac{13}{12} = 7 \frac{1}{12} [/tex]
[tex]d) \: 1 \frac{1}{3} \div 3 \frac{1}{5} = \frac{4}{3} \div \frac{16}{5} = \frac{4}{3} \times \frac{5}{16} = \frac{5}{12} [/tex]
Zadanie 6.
[tex]a) \: (6 - 5 \frac{4}{5} ) \times \frac{1}{6} = \frac{1}{5} \times \frac{1}{6} = \frac{1}{30} [/tex]
[tex]b) \: ( \frac{1}{5} - \frac{1}{8} ) \div 2 \frac{1}{4} = ( \frac{8}{40} - \frac{5}{40} ) \div \frac{9}{4} = \frac{3}{40} \times \frac{4}{9} = \frac{1}{30} [/tex]
[tex]c) \: \frac{1}{5} - ( \frac{3}{10} - \frac{2}{15} ) = \frac{1}{5} - ( \frac{9}{30} - \frac{4}{30} ) = \frac{1}{5} - \frac{5}{30} = \frac{6}{30} - \frac{5}{30} = \frac{1}{30} [/tex]
[tex]d) \:( \frac{1}{3} - \frac{1}{5} ) \div (2 \frac{3}{7} + 1 \frac{8}{14} ) = ( \frac{5}{15} - \frac{3}{15} ) \div (2 \frac{6}{14} + 1 \frac{8}{14} ) = \frac{2}{15} \div 4 = \frac{2}{15} \div \frac{4}{1} = \frac{2}{15} \times \frac{1}{4} = \frac{2}{60} = \frac{1}{30} [/tex]
Pozdrawiam serdecznie, liczę na naj
