Odpowiedź:
1)
[tex]\left \{ {{x+2-3y=9} \atop {\frac{x+2}{6}-2y =3} /*-6} \right.\\\\\left \{ {{x+2-3y=9} \atop {-x-2} +2y=-18} \\\\x+2-3y-x-2+2y=9-18\\-y=-9 /*(-1)\\y=9[/tex]
2)
[tex]\left \{ {{x+3-2y=10} \atop {{\frac{x+3}{4}-2y =4 /*-4}} \right. \\\left \{ {{x+3-2y=10} \atop {{-x-3}+8y =-16}} \right. \\\\\\x+3-2y-x-3+8y=10-16\\6y=-6\\y=-1[/tex]
