Odpowiedź :
Odpowiedź:
[tex]\frac{3}{5}+ 2\frac{1}{3}+5\frac{1}{3}+1\frac{2}{5}+\frac{2}{3}\\\\\frac{3}{5}+\frac{7}{3}+\frac{16}{3}+\frac{7}{5}+\frac{2}{3}=\frac{31}{3}=10\frac{1}{3}[/tex]
[tex]\frac{3}{5}+2\frac{1}{3}+5\frac{1}{3}+1\frac{2}{5}+\frac{2}{3} = \frac{3}{5}+1\frac{2}{5}+2\frac{1}{3}+5\frac{1}{3}+\frac{2}{3} =1\frac{5}{5}+7\frac{4}{3} = 2+8\frac{1}{3} = \boxed{10\frac{1}{3}}[/tex]