Wzór na przekątną prostopadłościanu
[tex] \sqrt{ {a}^{2} + {b}^{2} + {c}^{2} } [/tex]
Dane
[tex]a = 1dm = 10cm \\ \\ b = 6cm \\ \\ c = 8cm[/tex]
Obliczenia
[tex] \sqrt{ {10}^{2} + {6}^{2} + {8}^{2} } = \\ \\ = \sqrt{100 + 36 + 64} = \\ \\ = \sqrt{200} = \\ \\ = \sqrt{100 \times 2} = \\ \\ = \boxed{10 \sqrt{2} cm}[/tex]
