Odpowiedź:
1.
H H H H
\ / | |
C = C + Br - Br ---> H - C - C - H
/ \ | |
H H Br Br
eten brom dibromoetan
C2H4 + Br2 ----> C2H4Br2
eten brom dibromoetan
2.
C3H6 - propen
mC - 12g
mH - 1g
mC = 3 × 12g = 36g
mH = 6 × 1g = 6g
C : H
36 : 6
6 : 1
3.
C3H6 - propen
mC = 12g mC = 3 × 12g = 36g
mH = 1g mH = 6 × 1g = 6g
mC3H6 = 3 × 12g + 6 × 1g = 36g + 6g = 42g
42g ---- 100%
36g ----- x
36g × 100%
x = ---------------- = 85, 71 %
42g
%C = 85, 71 %
Wyjaśnienie:
:))
