Zadanie w załączniku BŁAGAM POMÓŻCIE daje najjj

a)
[tex]h = 3 \ cm\\r = 8 \ cm\\\\l^{2} = 3^{2}+8^{2}=9+64\\\\l^{2} = 73\\\\l = \sqrt{73} \ cm\\\\\\P_{p} = \pi r^{2}\\\\P_{b}=\pi rl\\\\P_{c} = \pi r^{2}+\pi rl\\\\\underline{P_{c} = \pi r(r+l)}\\\\\boxed{P_{c} = 8\pi(8+\sqrt{73}) \ cm^{2}}[/tex]
[tex]V = \frac{1}{3}P_{p}\cdot h\\\\\underline{V = \frac{\pi r^{2}h}{3}}\\\\V = \frac{\pi \cdot8^{2}\cdot\sqrt{73}}{3}\\\\\boxed{V = \frac{16\pi\sqrt{73}}{3} \ cm^{3}}[/tex]
b)
[tex]h = 8 \ cm\\r = 3 \ cm\\l = \sqrt{73} \ cm\\\\P_{c} = \pi r(r+l)\\\\\boxed{P_{c} = 3\pi(3+\sqrt{73}) \ cm^{2}}\\\\\\V = \frac{\pi r^{2}h}{3}\\\\V = \frac{\pi \cdot3^{2}\cdot8}{3}\\\\\boxed{V = 24\pi \ cm^{3}}[/tex]