Odpowiedź :
[tex]D:\\x\neq -1\\x\neq 1\\\\\frac{2x-3}{x+1}-\frac{1}{x-1}=1\\ \\ \frac{(2x-3)(x-1)-1(x+1)}{(x-1)(x+1)}=1\\ \\\frac{2x^2-2x-3x+3-x-1}{x^2-1}=1\\ \\\frac{2x^2-6x+2}{x^2-1}=1\\ \\2x^2-6x+2=x^2-1\\x^2-6x+3=0\\\\delta:36-4*1*3=36-12=24\\\sqrt{delta}=\sqrt{24}=2\sqrt{6}\\ \\ x_1=\frac{6-2\sqrt{6} }{2}=3-\sqrt{6}\\ x_2=\frac{6+2\sqrt{6} }{2}=3+\sqrt{6}\\ \\ x_1=ok.0.550\\ \\ odp:055[/tex]