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4 (3x-5) =
5(8m+2) =
-2(5t+8) =
-3(2a-7) =


Odpowiedź :

1]

[tex]4(3x-5)=4\cdot3x-4\cdot5=\boxed{12x-20}[/tex]

2]

[tex]5(8m+2)=5\cdot8m+5\cdot2=\boxed{40m+10}[/tex]

3]

[tex]-2(5t+8)=-2\cdot5t-2\cdot8=\boxed{-10t-16}[/tex]

4]

[tex]-3(2a-7)=-3\cdot2a-3\cdot(-7)=\boxed{-6a+21}[/tex]