[tex]x(x+16) > 5(x-6)\\x^2+16x > 5x-30\\x^2+11x+30 > 0\\x^2+5x+6x+30 > 0\\x(x+5)+6(x+5) > 0\\(x+6)(x+5) > 0\\x\in(-\infty,-6)\cup(-5,\infty)[/tex]
