[tex]zad.1\\\\l:~~y=-\dfrac{1}{2} x\\\\k:~~y=ax+b~~-szukana~~prosta\\\\k ~~\Vert ~~l~~\Leftrightarrow~~a=-\frac{1}{2}\\ \\k:~~y=-\dfrac{1}{2} x+b~~\land ~~A\in k~~\land ~~A=(6,0)\\\\-\dfrac{1}{2}\cdot 6 + b=0\\\\-3+b=0\\\\b=3\\\\k:~~y=-\dfrac{1}{2}x+3\\\\prosta~~k~~przecina~~os~~OY~~w~~punkcie ~~B~~gdzie~~B=(0,y):\\\\y=-\dfrac{1}{2} \cdot 0 +3\\\\y=3\\\\Odp:~~A.~~(0,3)[/tex]
[tex]zad.2\\\\sin135^{o} -cos45^{o} =?\\\\cos45^{o}=\dfrac{\sqrt{2} }{2} \\\\sin135^{o} =sin (180^{o} -45^{o} )=sin45^{o} =\dfrac{\sqrt{2} }{2} \\\\sin135^{o} -cos45^{o} =\dfrac{\sqrt{2} }{2}-\dfrac{\sqrt{2} }{2}=0\\\\A.~~sin90^{o} =1\\B.~~cos90^{o} =0\\C.~~cos180^{o} =-1\\D.~~cos0^{o} =1\\\\sin135^{o} -cos45^{o}=0~~\land ~~cos90^{o} =0~~\Rightarrow ~~poprawna ~~odpowiedz~~B.~~cos90^{o}[/tex]
