Odpowiedź :
CaC2 + 2 H2O -----> C2H2 + Ca(OH)2
mC2H2= 2*12u + 2*1u= 26 u
mCaC2= 1*40u + 2*12u= 64 u
64 g CaC2 -------- 26 g C2H2
128 g CaC2 ------- x
x= 52 g C2H2
d=m÷V
d*V=m
V=m÷d
V= 52 g÷ 1,07 g/cm3= 48,6 cm3
CaC2 + 2 H2O -----> C2H2 + Ca(OH)2
mC2H2= 2*12u + 2*1u= 26 u
mCaC2= 1*40u + 2*12u= 64 u
64 g CaC2 -------- 26 g C2H2
128 g CaC2 ------- x
x= 52 g C2H2
d=m÷V
d*V=m
V=m÷d
V= 52 g÷ 1,07 g/cm3= 48,6 cm3