Odpowiedź :
[tex]Dane:\\m = 20 \ kg\\r = 5 \ m\\v = 3\frac{m}{s}\\Szukane:\\F_{d} = ?\\\\Rozwiazanie\\\\\underline{F_{d} = \frac{mv^{2}}{r}}\\\\F_{d} = \frac{20 \ kg\cdot(3\frac{m}{s})^{2}}{5 \ m}\\\\\boxed{F_{d} = 36 \ N}[/tex]
[tex]Dane:\\m = 20 \ kg\\r = 5 \ m\\v = 3\frac{m}{s}\\Szukane:\\F_{d} = ?\\\\Rozwiazanie\\\\\underline{F_{d} = \frac{mv^{2}}{r}}\\\\F_{d} = \frac{20 \ kg\cdot(3\frac{m}{s})^{2}}{5 \ m}\\\\\boxed{F_{d} = 36 \ N}[/tex]