Pole dużego rombu
[tex] \frac{8 \times10 }{2} = 4 \times 10 = 40[/tex]
Pole małego rombu
[tex] \frac{4 \times 6}{2} = 4 \times 3 = 12[/tex]
Zatem pole figury to
[tex]40 - 12 = 28[/tex]
