Odpowiedź:
[tex]\sqrt[3]{2\frac{10}{27}}\cdot(-3^2:3,6+\sqrt{5\frac{19}{25}}-1,9)=\sqrt[3]{\frac{64}{27}}\cdot(-9:\frac{36}{10}+\sqrt{\frac{144}{25}}-1,9)=\\\\=\frac{4}{3}\cdot(-9:\frac{18}{5}+\frac{12}{5}-1,9)=\frac{4}{3}\cdot(-\not9^1\cdot\frac{5}{\not18_{2}}+\frac{12}{5}-\frac{19}{10})=\frac{4}{3}\cdot(-\frac{5}{2}+\frac{12}{5}-\frac{19}{10})=[/tex][tex]=\frac{4}{3}\cdot(-\frac{25}{10}+\frac{24}{10}-\frac{19}{10})=\frac{4}{3}\cdot(-\frac{44}{10}+\frac{24}{10})=\frac{4}{3}\cdot(-\frac{20}{10})=\frac{4}{3}\cdot(-2)=-\frac{8}{3}=-2\frac{2}{3}\\\\Odp.B[/tex]
