Odpowiedź:
[tex]b)\\\\\frac{x}{3}-2=2x-\frac{x+3}{6}\ \ /\cdot6\\\\2x-12=12x-(x+3)\\\\2x-12=12x-x-3\\\\2x-12=11x-3\\\\2x-11x=-3+12\\\\-9x=9\ \ /:(-9)\\\\x=-1\\\\\\c)\\\\\frac{3}{5}x-0,4=2(0,75-\frac{1}{5}x)+0,1\\\\\frac{3}{5}x-\frac{2}{5}=1,5-\frac{2}{5}x+\frac{1}{10}\ \ /\cdot10\\\\6x-4=15-4x+1\\\\6x-4=16-4x\\\\6x+4x=16+4\\\\10x=20\ \ /:10\\\\x=2[/tex]
