Odpowiedź :
[tex]-9x^{2}+6x = 1\\\\-9x^{2}+6x - 1 = 0 \ \ /:(-1)\\\\9x^{2}-6x+1 = 0\\\\(3x-1)^{2} = 0\\\\3x-1 = 0\\\\3x = 1 \ \ /:3\\\\\boxed{x_{o} = \frac{1}{3}}[/tex]
Odpowiedź:
- 9x² + 6x = 1
- 9x² + 6x - 1 = 0
a = - 9 , b = 6 , c = - 1
Δ = b² - 4ac = 6² - 4 * ( - 9) * ( - 1)1 = 36 - 36 = 0
x₁ = x₂ = - b/2a = - 6/(- 18) = 6/18 = 1/3