Odpowiedź :
Hej,
a=0.2m/s^2
t=4s
s=at^2/2=0.2*4^2/4=1.6m
Droga hamowania wynosiła 1.6m
[tex]Dane:\\t = 4 \ s\\a = 0,2\frac{m}{s^{2}}\\Szukane:\\s = ?\\\\s = \frac{1}{2}at^{2}}\\\\s = \frac{1}{2}\cdot0,2\frac{m}{s^{2}}\cdot(4 \ s)^{2}}\\\\s = 0,1\frac{m}{s^{2}}\cdot16 \ s^{2}\\\\\boxed{s = 1,6 \ m}[/tex]