👤
ANIA6659ON
Rozwiązane

Zad 2 str 109 proszę bardzo

Zad 2 Str 109 Proszę Bardzo class=

Odpowiedź :

LOCZEEQON

a)

[tex] \frac{ {a}^{2} \sqrt{3} }{4} = 9 \sqrt{3} | \times 4 \\ {a}^{2} \sqrt{3} = 36 \sqrt{3} | \div \sqrt{3} \\ {a}^{2} = 36 \\ a = 6[/tex]

Obwód

[tex]3 \times 6 = 18cm[/tex]

b)

[tex] \frac{ {a}^{2} \sqrt{3} }{4} = 25 \sqrt{3} | \times 4 \\ {a}^{2} \sqrt{3} = 100 \sqrt{3} | \div \sqrt{3} \\ {a}^{2} = 100 \\ a = 10[/tex]

[tex] \frac{ {a}^{2} \sqrt{3} }{4} = \sqrt{3} | \times 4 \\ {a}^{2} \sqrt{3} = 4 \sqrt{3} | \div \sqrt{3} \\ {a}^{2} = 4 \\ a = 2[/tex]

Obwód

[tex]3 \times 2 = 6m[/tex]

Obwód

[tex]3 \times 10 = 30dm[/tex]

c)

ZBIORJON

[tex]Wzor~~na~~pole~~\Delta~~rownobocznego:\\\\P=\dfrac{a^{2}\sqrt{3} }{4} ~~gdzie~~a-dlugosc~~boku~~\Delta~~rownobocznego\\\\Obw=3\cdot a\\\\zad.2\\\\a)\\\\P=9\sqrt{3} ~cm^{2} ~~\land ~~P=\dfrac{a^{2}\sqrt{3} }{4}~~\Rightarrow ~~ \dfrac{a^{2}\sqrt{3} }{4}=9\sqrt{3}~cm^{2} ~~\Rightarrow ~~a^{2} =36~cm^{2}~~ \Rightarrow ~~a=6~cm\\\\Obw=3\cdot 6~cm = 18~cm[/tex]

[tex]b)\\\\P=25\sqrt{3} ~dm^{2} ~~\land ~~P=\dfrac{a^{2}\sqrt{3} }{4}~~\Rightarrow ~~ \dfrac{a^{2}\sqrt{3} }{4}=25\sqrt{3}~dm^{2} ~~\Rightarrow ~~a^{2} =100~dm^{2}~~ \Rightarrow ~~a=10~dm\\\\Obw=3\cdot 10~dm = 30~dm\\\\c)\\\\P=\sqrt{3} ~m^{2} ~~\land ~~P=\dfrac{a^{2}\sqrt{3} }{4}~~\Rightarrow ~~ \dfrac{a^{2}\sqrt{3} }{4}=\sqrt{3}~m^{2} ~~\Rightarrow ~~a^{2} =4~m^{2}~~ \Rightarrow ~~a=2~m\\\\Obw=3\cdot 2~m = 6~m[/tex]

On Studier: Inne Pytanie