Odpowiedź :
[tex](2x+6)(x+4)=2x^2+8x+6x+24=2x^2+14x+24\\(3a+6)(a+3)=3a^2+9a+6a+18=3a^2+15a+18\\(2x+2y)(x+y)=2x^2+2xy+2xy+2y^2=2x^2+4xy+2y^2\\(4a+b)(7+b)=28a+4ab+7b+b^2\\(a+5)(a+5)=a^2+5a+5a+25=a^2+10a+25\\(2m+2)(2m-3)=4m^2-6m+4m-6=4m^2-2m-6[/tex]
[tex](2x+6)(x+4)=2x^2+8x+6x+24=2x^2+14x+24\\(3a+6)(a+3)=3a^2+9a+6a+18=3a^2+15a+18\\(2x+2y)(x+y)=2x^2+2xy+2xy+2y^2=2x^2+4xy+2y^2\\(4a+b)(7+b)=28a+4ab+7b+b^2\\(a+5)(a+5)=a^2+5a+5a+25=a^2+10a+25\\(2m+2)(2m-3)=4m^2-6m+4m-6=4m^2-2m-6[/tex]