Odpowiedź:
zad 1
a)
[tex]\frac{p}{5} [/tex]
b)
[tex] \frac{ {x}^{2} + x }{2} [/tex]
c)
[tex] \frac{2}{3} n[/tex]
zad2
[tex]2k - 1 \\ 2k + 1 \\ 2k + 3[/tex]
zad3
[tex]x = - 2 \\ - 4(2x + 5) = - 4(2( - 2) + 5) = - 4( - 4 + 5) = - 4[/tex]
zad4
[tex] - 3.2 {x}^{2} {y}^{2} 1.5 {x}^{3} y = {x}^{5} {y}^{3} ( - 3.5)(1.5) = {x}^{5} {y}^{3} ( - 4.8) = - 4.8{x}^{5} {y}^{3} [/tex]
zad5
a) wszytskie to wyrazy podobne
b) 1 i 2
c) 1 i 3
d) brak wyrazów podobnych
zad 6
a)
[tex]3a + 7 - 4a + 5 + 5a - 2 = 4a + 10 \\ \\ a = - 3 \\ 4( - 3) + 10 = - 12 + 10 = - 2[/tex]
b)
[tex]2x + 2y + 5 - 3x + 3y = - x + 5y + 5 \\ \\ x = 3 \: \: y = - 0.2 \\ - (3) + 5( - 0.2) + 5 = - 3 - 1 + 5 = 1[/tex]
zad7
[tex](4x - 5) - (2 + x) = 4x - 5 - 2 - x = 3x - 7[/tex]
odp B
zad 8
[tex] - 2(5a + 4b) = - 10a - 8b[/tex]
odpowiedź C
zad9
[tex]a - 4b + 4(a - b) = a - 4b + 4a - 4b = 5a - 8b[/tex]
odpowiedź A
zad 10
[tex] {b}^{2} - ( \frac{1}{2} {b}^{2} ) - ( \frac{1}{2} (b - 2)(b - 1)) = \frac{1}{2} {b}^{2} - \frac{1}{2} ( {b}^{2} - b - 2b + 2) = \frac{1}{2} {b}^{2} - \frac{1}{2} {b}^{2} + \frac{3}{2} b + 1 = \frac{3}{2} b - 1[/tex]
zad11
[tex]v = ph = {(20 - a)}^{2} a = ( {20}^{2} - 40a + {a}^{2} )a = 400a - 40 {a}^{2} + {a}^{3} \\ \\ a = 3 \\ v = 400 \times 3 - 40 \times {3}^{2} + {3}^{3} = 1200 - 360 + 27 = 867[/tex]
