Odpowiedź:
[tex]\left \{ {{4x-8=2y} \atop {5x+3y=9}} \right.\\ \left \{ {{x=-\frac{1}{2}+2 } \atop {5x+3y=9}} \right. \\5(-\frac{1}{2}y+2)+3y=9\\ y=-2\\x=-\frac{1}{2}x(-2)+2\\ x=3\\(x,y)=(3,,-2)\\\left \{ {{4x3-8=-2x(-2)} \atop {5x3+3x(-2)=9}} \right. \\\left \{ {{4=4} \atop {9=9}} \right.\\ (x,y)=(3.-2)[/tex]
[tex]\left \{ {{x+3y=5} \atop {2x-5y=10}} \right.\\ \left \{ {{x=5-3y} \atop {2x-5y=10}} \right.\\ 2(5-3y)-5y=10\\y=0\\x=5-3x0\\x=5\\(x,y)=(5.0)\\\left \{ {{5+3x0=5} \atop {2x5-5x0=10}} \right.\\ \left \{ {{5=5} \atop {10=10}} \right\\.(x,y)=(5,0)[/tex]
[tex]\left \{ {{\frac{1}{3}-1=y } \atop {x-3y=3}} \right.\\ x-3(\frac{1}{3}x-1)=3\\[/tex]
x∈R
[tex](x,y)=(x,\frac{1}{3}x-1)[/tex]
Szczegółowe wyjaśnienie:
