potrzebuje pomocy z zadaniem 11 z rozwiazaniem!!

Wzór na objętość ostrosłupa:
[tex]V= \dfrac{1}{3} \cdot H\cdot P_{p} ~~gdzie:\\V~~-objetosc\\H~~-wykososc~~ostroslupa\\P_{p}~~ -pole~~podstawy[/tex]
[tex]zad.11\\a)\\V=290~cm^{3} ,~~P_{p}=90~cm^{2} \\\\podstawiam ~~do~~wzoru~~na~~objetosc:\\\\290~cm^{3}=\dfrac{1}{3}\cdot H\cdot 90~cm^{2}\\\\H\cdot 30~cm^{2}=290~cm^{3} ~~\mid \div 30~cm^{2}\\\\H=\dfrac{290}{30} ~cm\\\\H=9\dfrac{2}{3} ~cm~~\Rightarrow~~H~~jest ~~mniejsza~~niz~~10~cm\\\\Odp:~~P\\\\b)\\V=177~cm^{3} ,~~H=27~cm\\\\podstawiam ~~do~~wzoru~~na~~objetosc:\\\\177~cm^{3}=\dfrac{1}{3}\cdot 27~cm\cdot P_{p} \\\\9~cm\cdot P_{p} =177~cm^{3}~~\mid \div 9~cm\\\\[/tex]
[tex]P_{p} =\dfrac{177}{9} ~cm^{2} \\\\P_{p} =19\dfrac{2}{3} ~cm^{2} ~~\Rightarrow~~P_{p} ~~jest~~mniejsze~~niz~~20~cm^{2} \\\\Odp:~~F[/tex]