Odpowiedź:
a) [tex](\frac{3}{4} +\frac{2}{3})*6=(\frac{9}{12}+\frac{8}{12})*6=\frac{17}{12}*6=\frac{17}{2} *1=8\frac{1}{2}[/tex]
b) [tex]1\frac{5}{6} -2*\frac{3}{4} =\frac{11}{6}-\frac{6}{4}=\frac{22}{12}-\frac{18}{12} =\frac{4}{12}=\frac{1}{3}[/tex]
c) [tex]1\frac{7}{10} *10+3*1\frac{1}{12}=\frac{17}{10}*10 +3*\frac{13}{12}=17+\frac{39}{12}=17+3\frac{3}{12}=20\frac{3}{12}=20\frac{1}{4}[/tex]
